p. 1

algebraic expression the algebraic expressions have the variables and the constants the algebraic expressions are the finite combination of the symbols that are formed according to the rules of the context the algebra is an expression which is used to designate the value for the given values in the expression the expression might be depending on the values assigned to the values assigned in the expression the expression is the syntactic concept in the algebra the online provides the connectivity between the tutors and the students this article has the information about learn online algebraic expressions simplifying algebraic expressions below are the examples on simplifying algebraic expressions know more about adding and subtracting fractions worksheets

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p. 2

example 1 compute the factors for the expression x2 56x 768 solution the given expression is x2 56x 768 step 1 x2 56x 768 x2+24x 32x 24x 32 step 2 x2 56x 768 xx+24 32x +24 step 3 x2 56x 768 x+24 x+32 step 4 x+24 and x+32 the factors for the given expression x2 56x 768 are x +24 and x +32 example 2 compute the factors for the expression x2 76x 1440 solution the given expression is x2 76x 1440 step 1 x2 76x 1440 x2+36x 40x 36x 40 step 2 x2 76x 1440 xx+36 40x +36 learn more about decimal worksheets

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p. 3

step 3 x2 76x 1440 x+36 x+40 step 4 x+36 and x+40 the factors for the given expression x2 76x 1440 are x +36 and x +40 example 3 simplify the expression 24xy 10 x2y 14 x y 16 x2y 10 x y solution :the given expression is 24xy 10 x2y 14 x y 16 x2y 10 x y step 1 24xy 10 x2y 14 x y 16 x2y 10 x y x y 24 +14 +10 x2y 10 16 step 2 24xy 10 x2y 14 x y 16 x2y 10 x y 48 x y x2y 10 16 step 3 24xy 10 x2y 14 x y 16 x2y 10 x y 48 x y 26 x2y the value for the given expression 12xy 13 x2y 16 x y 20 x2y is 48 x y 26 x2y algebraic expressions practice problems below are the practice problems on algebraic expressionsdetermine the value for the algebraic expression x2 50x 600 answer x 30 x 20 simplify the expression 80 x y 15 x2y 5 x y 17 x2y answer 85 x y 32 x2y.

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p. 4

perfect square trinomial introduction perfect square trinomial is the product of two binomials but both the binomials are same when factoring some quadratics which gives identical factors that quadratics are perfect square trinomial the general form of perfect square trinomial is ax-b 2 ax2-2axb+b2 and ax+b 2 ax2 2axb b2 in this the first term and last term of the perfect square are perfect squares and the middle term is 2 times the square root of first terms times and square root of last terms perfect square trinomial example problems x2+4x+4 =0 in this the first term is x2 the second term is 2 times the square root of first term and square root of second term and the third term 4 can be written as 22 which is a perfect square x2+2 × × 22 0 this is the perfect square trinomial.

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p. 5

x2+8x+16=0 in this the first term is x2 the second term is 2 times the square root of first term and square root of second term and the third term 16 can be written as 42 which is a perfect square x2 2 × × 42 0 this is the perfect square trinomial x2+10x+5 × 5 0 in this the first term is x2 the second term is 2 times the square root of first term and square root of second term and the third term 25 can be written as 52 which is a perfect square x2+2 × × 52 0 this is the perfect square trinomial factoring perfect square trinomialback to top factor the trinomial x2+4x+4=0 solution given x2+4x+4=0 the above trinomial can be written as x2+2x+2x+4=0 read more about graphing worksheets

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p. 6

take x as common from first two terms xx+2 2x+4=0 take 2 as common from last two terms xx+2 2x+2 0 x+2 x+2 0 in this it is the product of two identical binomials x+22=0 which is a perfect square.

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p. 7

thank you tutorvista.com

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